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Wilson
United States > Wyoming > Teton County
Wilson is located at 43°29′11″N 110°52′45″W / 43.48639°N 110.87917°W / 43.48639; -110.87917 (43.4863, -110.8793). at an elevation of 6,148 feet (1,874 m) above sea level.
Average elevation: 2,082 m